Asked by John
State an equation of a rational function that satisfies the given conditions: vertical asymptote at x=5, horizontal asymptote at y=-3, and x-intercept is 5/2.
Need help solving.
Need help solving.
Answers
Answered by
Steve
vertical asymptote at x=5
y = 1/(x-5)
horizontal asymptote at y=-3
y = -3x/(x-5)
x-intercept is 5/2
Change the x to (x - 5/2)
y = -3(x - 5/2)/(x-5)
See the graph at
www.wolframalpha.com/input/?i=-3(x+-+5%2F2)%2F(x-5)
y = 1/(x-5)
horizontal asymptote at y=-3
y = -3x/(x-5)
x-intercept is 5/2
Change the x to (x - 5/2)
y = -3(x - 5/2)/(x-5)
See the graph at
www.wolframalpha.com/input/?i=-3(x+-+5%2F2)%2F(x-5)
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