Question

State an equation of a rational function that satisfies the given conditions: vertical asymptote at x=5, horizontal asymptote at y=-3, and x-intercept is 5/2.
Need help solving.

Answer 1

vertical asymptote at x=5
y = 1/(x-5)

horizontal asymptote at y=-3
y = -3x/(x-5)

x-intercept is 5/2
Change the x to (x - 5/2)
y = -3(x - 5/2)/(x-5)

See the graph at
www.wolframalpha.com/input/?i=-3(x+-+5%2F2)%2F(x-5)