Question
two buses leave a bus station and travel in opposite directions from that same starting point. if the speed of the other is twice the speed of the other and they are 240km apart at the end of one hour, what is the speed of each bus?
Answers
fiyinfoluwa.
solve it for me
Reiny
Rate of one --- x
rate of the other --- 2x
They both drove for 1 hour, so their distance are 1(x) and 1(2x) km
connect the dots for me.
rate of the other --- 2x
They both drove for 1 hour, so their distance are 1(x) and 1(2x) km
connect the dots for me.
Henry2
V1 = X km/h.
V2 = 2x km/h.
d1 = V1 * t = x * 1 = X km.
d2 = V2 * t = 2x * 1 = 2x km.
d2 - d1 = 2x - x = 240.
X = 240 km. = d1.
2x = 2 * 240 = 480 km. = d2.
d1 = V1 * t = 240,
V1 * 1 = 240,
V1 = 240 km/h.
d2 = V2 * t = 480,
V2 * 1 = 480,
V2 = 480 km/h.
Was it 2 buses or 2 planes?
The speed is too high for a bus.
V2 = 2x km/h.
d1 = V1 * t = x * 1 = X km.
d2 = V2 * t = 2x * 1 = 2x km.
d2 - d1 = 2x - x = 240.
X = 240 km. = d1.
2x = 2 * 240 = 480 km. = d2.
d1 = V1 * t = 240,
V1 * 1 = 240,
V1 = 240 km/h.
d2 = V2 * t = 480,
V2 * 1 = 480,
V2 = 480 km/h.
Was it 2 buses or 2 planes?
The speed is too high for a bus.
Henry2
V1 = X km/h.
V2 = 2x km/h.
d1 = V1 * t = X * 1 = X km.
d2 = V2 * t = 2x * 1 = 2x km.
d2 - d1 = 2x - (-x) = 240 km.
2x + x = 240,
X = 80 km = d1.
d2 = 2x = 2 * 80 = 160 km.
d1 = V1 * t = 80,
V1 * 1 = 80,
V1 = 80 km/h.
d2 = V2 * t = 160,
V2 * 1 = 160,
V2 = 160 km/h.
V2 = 2x km/h.
d1 = V1 * t = X * 1 = X km.
d2 = V2 * t = 2x * 1 = 2x km.
d2 - d1 = 2x - (-x) = 240 km.
2x + x = 240,
X = 80 km = d1.
d2 = 2x = 2 * 80 = 160 km.
d1 = V1 * t = 80,
V1 * 1 = 80,
V1 = 80 km/h.
d2 = V2 * t = 160,
V2 * 1 = 160,
V2 = 160 km/h.