Asked by Keonn'a
The formula h=vt−16t^2 gives the height h, in feet, of an object projected into the air with an initial vertical velocity v, in feet per second, after t
seconds.
If an object is projected upward with an initial velocity of
112 feet per second, at what times will it reach a height of
160 feet above the ground?
seconds.
If an object is projected upward with an initial velocity of
112 feet per second, at what times will it reach a height of
160 feet above the ground?
Answers
Answered by
R_scott
160 = 112 t - 16 t^2
solve for t
solve for t
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