Asked by Brenda

Use the quadratic formula to find the real solutions of the equation 2x^2-3x=1
Answered by Brenda
I really need help with this one because I was absent for this portion of the notes because I got called down to guidance can someone please help me and explain this to me
Answered by Damon
2 x^2 - 3 x - 1 = 0
x = [ 3 +/- sqrt (9+8) ] / 4

= [ 3 +/- sqrt(17) ] / 4
Answered by Damon
well
if a x^2 + b x + c = 0
then
x = [ -b +/- sqrt(b^2-4ac) ] / 2a
Answered by Brenda
Thank you so very much Damon.
Answered by Damon
You are welcome.
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