Asked by ryancon

We just had a lab where our objective was to find the molar mass of Copper using electrolysis. A question on my post lab asks:

Would it make a difference if Cu(NO3)2, instead of CuSO4, we’re used in the copper half cells in this experiment? Why or why not?

If more info is needed let me know. Anything helps!
Answered by Star
information
Answered by ryancon
Using four electrodes (two copper in the electrolytic cell, one copper and one zinc in the galvanic cell), we put them in CuSO4 solution for 45 minutes to see a redox reaction occur while measuring milliamps. The milliamps went from 30.4 initially to 30.9 in the end. Will the results be affected if Cu(NO3)2 was used instead of CuSO4?
Answered by DrBob222
Cu(NO3)2 and CuSO4 should produce the same results.
There are no AI answers yet. The ability to request AI answers is coming soon!