Solve

q+12-2(q-22) > 0

Can I get help on how to solve this? I'm really stuck on it

8 answers

q+12-2(q-22) > 0
q + 12 - 2q + 44 > 0
-q > -56
q < 56
dis right?
I'm still confused
q<56
I'm still confused
for those still confused,
q + 12 - 2 (q - 22) >0
first you are going to subtract 12 from the equation, (which is just pretty much just subtracting 12 from 0. the equation will now be this,
q - 2 (q - 22) > -12
now solve the parenthesis. multiply the -2 by the q and 22 (-2q + 44)
your equation will now look like this,
q - 2q + 44 > -12
now combine like terms, q - 2q = -q the equation is now,
-q + 44 > -12
subtract 44 from the equation, -12 - 44 = -56
now we have -q > -56
now reverse the inequality
final answer: q < 56
hope this helps!
Getting Rid of Negative Variables (Simplifying Math)
by Eric Buffington
0:54 explains the last bit lads
hi
Similar Questions
  1. Use your knowledge of exponents to solve.a) 1/2^x=1/(x+2) b) 1/2^x>1/x^2 So I know that these functions are rational functions..
    1. answers icon 1 answer
  2. Solve by the system of equations by substitution.x + 2y + z = 14 y = z + 1 x = -3z + 6 Anyone able to help me with this? I've
    1. answers icon 1 answer
  3. For # 1, im getting stuck on this problem i don't understand this1.4 = e ^ (0.03k) Now take the natural logarithm of both sides
    1. answers icon 1 answer
    1. answers icon 2 answers
more similar questions