Asked by melissa

Superman is said to be able to ''leap buildings in a single bound'' How high a building could Superman jump over if he were to leave the ground with speed of 98.0 m/s at an angle of 87.0 degrees to the horizontal?

Answers

Answered by R_scott
h = -1/2 g t^2 + [98.0 sin(87.0º)]

the max is on the axis of symmetry ... t = -b / 2a = -[98.0 sin(87.0º)] / -g

solve for t ... plug into h equation to find max height
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