the jewelry box will have rectangular sides and an open top. the longer sides will be made of gold at a cost of $300/in^2 and the shorter sides will be made from platinum at a price of $550/in^2. the bottom of the box will be made from plywood at a cost of $.02/in^2. what dimensions will provide me with the lowest cost if i would like the box to have a volume of 50in^3?

1 answer

If the length is x and the width is y, and the height is z, then
xyz = 50, so z = 50/(xy)
The area is
a(x,y) = 2(xz+yz+xy)
and so the cost is
c(x,y) = 2(300xz+550yz+0.02xy)
= 2((300x+550y)(50/(xy))+0.02xy)
Now, normally, I'd set ∂c/∂x=0 and ∂c/∂y = 0 and solve for x and y, but when I do that here, I get a ridiculously small value for z, since the cost of the sides is so much greater than that of the bottom. You sure there are no typos?