Asked by Anonymous

Graph the parabolas and identify the axis, directrix, and focus: (y^2)+8x=0
I know that the axis refers to the axis of symetry and the directrix is the same distance away from the vertex as the foucus is. I just don't know how to graph and identify all the parts from an equation like the one above.
Answered by Steve
Recall that the parabola

y^2 = 4px

has
vertex at (0,0)
focus at (p,0)
directrix at x = -p

(y^2)+8x=0
can be written as

y^2 = -8x
so p = -2
now just plug and chug.

It is clearly a parabola opening to the left with vertex at (0,0).
Answered by Anonymous
Thank you so much Steve!! just two questions, what does the variable "p" stand for/ represent and could I be able to represent the axis of symetry as an equation/point.
Answered by Anonymous
wait dose the axis even mean the axis of symetry??
Answered by Steve
yes, "axis" means the axis of symmetry.
and yes, your parabola has the x-axis as its axis of symmetry.

y = 0
Answered by Anonymous
thanks you so much!!
Answered by Gerald Zea
Can someone help me please.
How to find the equation of the axis of parabola and its length of the latus rectum having y-x²+8x=0?
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