about the second block first:
m v before = m v after
0.0035 v = 1.80035 (1.4)
v = 720 m/s
well that was part (a)
now part (b)
0.0035 u = 1.2 (0.63) + 0.0035 (720)
solve for u
A 3.5 g bullet is fired horizontally at 2 blocks resting on a smooth tabletop. The bullet passes trough the 1st block, with mass 1.2 kg and embed itself in the second with mass 1.8 kg. Speeds of 0.63 m/s and 1.4 m/s, respectively are there by imparted on the blocks. Neglecting the mass removed from the first block by the bullet, find (a) the speed of the bullet immediately after it emerges from the 1st block and (b) bullets original speed.
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