Asked by Luke

friction force does -200 J of work on a baseball player of mass 45.0 kg when she has stopped after sliding into second base. what was her initial velocity?
Answered by Henry2
KE = 0.5M*V^2 = 200.
0.5*45*V^2 = 200,
V = ?

Answered by Anonymous
(1/2) m v^2 = Ke = work done to stop = 200

22.5 v^2 = 200
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