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A ball is projected horizontally from top of a hill with a velocity of 30m/s.If it reaches the ground 5 seconds later, calculat...Asked by Ande2
A ball is projected horizontally from the top of a hill with a velocity of 30m/s.If it reaches the ground 5 seconds later, calculate the height of the hill, take g=10 metres per second square.
Answers
Answered by
R_scott
same answer
Answered by
Muinat
U=30m/s
T=5secs
H=?
S=ut+1/2gt^2=0×5×4^2=80metres
T=5secs
H=?
S=ut+1/2gt^2=0×5×4^2=80metres
Answered by
Saadat
H=ut +1/2gt×t
30×5+1/2×10×5×5
150+125
=275
30×5+1/2×10×5×5
150+125
=275
Answered by
joshua
a Ball is projected horizontally from the hill with a velocity of 30m if it reaches the ground 5seconds later calculate the height
Answered by
Divine
My answers is 125 why
Answered by
Bada monei
H=ut+1\2gt"2 but since its horizntally from the top of a hill,the laws says that u=0,so it will be 1\2gt"2,1\2*10*5"2=5*25,then the answer is 125m
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