Asked by Ande2

A ball is projected horizontally from the top of a hill with a velocity of 30m/s.If it reaches the ground 5 seconds later, calculate the height of the hill, take g=10 metres per second square.
Answered by R_scott
same answer
Answered by Muinat
U=30m/s
T=5secs
H=?
S=ut+1/2gt^2=0×5×4^2=80metres
Answered by Saadat
H=ut +1/2gt×t
30×5+1/2×10×5×5
150+125
=275
Answered by joshua
a Ball is projected horizontally from the hill with a velocity of 30m if it reaches the ground 5seconds later calculate the height
Answered by Divine
My answers is 125 why

Answered by Bada monei
H=ut+1\2gt"2 but since its horizntally from the top of a hill,the laws says that u=0,so it will be 1\2gt"2,1\2*10*5"2=5*25,then the answer is 125m
There are no AI answers yet. The ability to request AI answers is coming soon!