Asked by tiolu
The first and the last term of an AP are 6.7 and 17.1 respectively. If there are 14 terms in the sequence find the common difference
Answers
Answered by
tiolu
Pls how do i solve it
Answered by
Steve
The 14th term is 13 terms after the 1st.
So, the common difference is
(17.1-6.7)/13 = 0.8
So, the common difference is
(17.1-6.7)/13 = 0.8
Answered by
Daviyoung
Solve it
Answered by
Idris
Solve it fully
Answered by
Idris
Solve the question fully from the beginning
Answered by
Idris
I don't understand how you solve the question
Answered by
[email protected]
The 14th term is 13 terms after the 1st.
So, the common difference is
formular(first term-last term / the number of terms in the squence)
(17.1-6.7)/13 = 0.8
So, the common difference is
formular(first term-last term / the number of terms in the squence)
(17.1-6.7)/13 = 0.8
Answered by
Israel akinola
Correct
Answered by
chrisy@gmail
correct
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Answered by
Anonymous
Jeremiah
Answered by
Anonymous
Promise
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