The first and the last term of an AP are 6.7 and 17.1 respectively. If there are 14 terms in the sequence find the common difference

11 answers

Pls how do i solve it

The 14th term is 13 terms after the 1st.
So, the common difference is

(17.1-6.7)/13 = 0.8

Solve it

Solve it fully

Solve the question fully from the beginning

I don't understand how you solve the question

The 14th term is 13 terms after the 1st.
So, the common difference is

formular(first term-last term / the number of terms in the squence)

(17.1-6.7)/13 = 0.8

Correct

correct
cf

Jeremiah

Promise

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