Asked by Lonely

Find the four complex roots of (z^2 + 2)^2 + 2 = z

I expanded it and got z^4+4z^2-z+6=0, not sure where to go from here
Answered by Damon
z^4+4z^2-z+6=0 is correct
then
https://www.mathportal.org/calculators/polynomials-solvers/polynomial-roots-calculator.php
Answered by Damon
note quartic method there
https://www.mathportal.org/formulas/algebra/solalgebric.php
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