Question

A dust particle carrying a charge of -3 x 10-10 C is 2mm to the left of another dust particle carrying a charge of +4 x 10-10C. Find the magnitude and direction of the electric force on the first particle.
opposite charges attract so force to the left
d = 0.002 meter
k = 9*10^9

-k Q1Q2/d^2
oh, sorry, did not read carefully. They want force on FIRST so equal and opposite, to the right, positive

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