mass = 1360 kg = m
Vi = 26.8
v = Vi + a t
0 = 26.8 + 4.18 t
so
a = -26.8/41.8
use that a
x = 0 + 26.8 t -(1/2)(26.8/41.8) t^2
ah come on F = m a
A car which has a mass of 1.36 tonnes is travelling at 26.8m/s on a level road when the driver brings the car to an emergency stop using only the brakes. A time interval of 4.18s is required to bring the car to a stop.
1. Calculate the position of the car while the car is coming to a stop. Assume x ₀= 0
2. Calculate the braking force acting on the car while the car comes to a stop.
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