Question
A car has a velocity of 14.2m/s^2 when the driver decides to accelerate at 6.80m/s^2 for 2.40s. The initial position of the car is 100m
a) What is the velocity vector of the car at t=2.40s?
b) What is the position of the car at t = 2.40s?
c) what is the displacement of the car at the end at t = 2.40s?
a) What is the velocity vector of the car at t=2.40s?
b) What is the position of the car at t = 2.40s?
c) what is the displacement of the car at the end at t = 2.40s?
Answers
bobpursley
assuming initial velocity vi=14.2 m/s
final velocity=vi+at=14.2+6.8*2.40=???
Position=vi*2.40+1/2 * 6.8*2.40^2+100
displacement =position-100
final velocity=vi+at=14.2+6.8*2.40=???
Position=vi*2.40+1/2 * 6.8*2.40^2+100
displacement =position-100