Asked by Olajumoke

If the sixth term of an A.P is 37 and the sum of the first sixth term is 147.find the first term and the sum of the first 15 terms
Answered by Steve
a+5d = 37
6/2 (2a+5d) = 147
Now just solve for a and d, and
S15 = 15/2 (2a+14d)
Answered by Dami
a+(n-1)d =37
n/2 (2a+(n-1)d=147
So a+5d=37 eqn 1=37
3(2a +5d) eqn 2=147
Use elimination
a= 12
Answered by Dami
a+5d = 37
12+5d = 37
5d = 37- 12 = 25
5d = 25
d = 5
Answered by Dami
n/2 (2a+ (n-1)d
15/2 [2(12) +14d]
15/2 [24 + 14×5]
15/2 [24 + 70]
15/2 [ 94]
15× 47= 705.
Answered by Adetoun
U have to show the working to the reader understanding
Answered by Tosin
Please how does this u lesson operate
Answered by Anonymous
In an Ap the difference between the 8 term is half times the 4 term. find the common difference and the first term
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