Asked by Anonymous
Molarity of NaNo by diluting 250.0 of a 1.60 solution to a final volume of 400cm3
Answers
Answered by
Damon
original concentration is 1.6 mols in 1000cm^3
so mols in original 250 cc = (1/4)(1.6) = 0.4 mols
same mols in final
so
0.4 / 400 = M/1000
M = 400/400 = 1.00
so mols in original 250 cc = (1/4)(1.6) = 0.4 mols
same mols in final
so
0.4 / 400 = M/1000
M = 400/400 = 1.00
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