a) not black ---> white
so you could have WB or BW
prob(WB or BW) = (1/2)(1/2) + (1/2)(1/2) = 1/2
or, think of it this way:
outcomes are WW, WB, BW, BB for a total of 4 possibilities, both W and B have equal likely outcomes
two of those are the outcomes you want ---> 2/4 = 1/2
b.) exactly 1 club. , let X be non-club
prob(club) = 13/52 = 1/4
prob(X) = 3/4
you want Prob(CX or XC) = (1/4)(3/4) + (3/4)(1/4) = 3/8
do c) following the method of b)
You draw a card from a deck of
52
cards twice, each time replacing the card. Find the following probabilities (rounded to the nearest thousandths) of observing:
a.) exactly 1 black card.
P(1 black card)=
b.) exactly 1 club. P(1 club)=
c.) exactly 1 two. P(1 two)
1 answer
1 answer