Asked by Anonymous
                if (x,y) is a solution to the system of equations above and x > 0 what is the value of x?
y-x^2 +2 = 9x
y = 4x + 4
What is the value of y in the solutions of the system of equations above?
8x-4y =7
5y - 4x = 10
            
        y-x^2 +2 = 9x
y = 4x + 4
What is the value of y in the solutions of the system of equations above?
8x-4y =7
5y - 4x = 10
Answers
                    Answered by
            Reiny
            
    for the first, use substitution , that is, replace the y in the first with the value of y of the 2nd
y-x^2 +2 = 9x
4x+4 - x^2 + 2 = 9x
-x^2 - 5x + 6 = 0
x^2 + 5x - 6 = 0
take over, you have a nice quadratic which factors.
remember x > 0 , so reject the negative x value
In the second pair, I would multiply the 2nd equation by 2 and then add them.
easy after that
    
y-x^2 +2 = 9x
4x+4 - x^2 + 2 = 9x
-x^2 - 5x + 6 = 0
x^2 + 5x - 6 = 0
take over, you have a nice quadratic which factors.
remember x > 0 , so reject the negative x value
In the second pair, I would multiply the 2nd equation by 2 and then add them.
easy after that
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