In the experiment, you will study a torsion pendulum and compare the periods of a suspended sphere and of a suspended cube. The rotational inertia of a sphere is Is = 1/10(MsD^2), where Ms is the mass of the sphere and D is its diameter. The rotational inertia of a cube is Ic = 1/6(McS^2), where Mc is the mass of the cube and S is the length of its side. If the cube and the sphere are suspended from the same wire, what is the expected ratio of their periods, Tc/Ts?

Assume that D = S,
Ms = 0.20kg,
and Mc = 0.6 kg.
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To find the ratio Tc/Ts, I tried doing:
(1/6 * 0.6) / (1/10 * .2) = 5, but this is incorrect.
What am I missing?

asked by John

6 years ago

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Question

In the experiment, you will study a torsion pendulum and compare the periods of a suspended sphere and of a suspended cube. The rotational inertia of a sphere is Is = 1/10(MsD^2), where Ms is the mass of the sphere and D is its diameter. The rotational inertia of a cube is Ic = 1/6(McS^2), where Mc is the mass of the cube and S is the length of its side. If the cube and the sphere are suspended from the same wire, what is the expected ratio of their periods, Tc/Ts? 
Assume that D = S, 
Ms = 0.20kg, 
and Mc = 0.6 kg. 
-----------------------
To find the ratio Tc/Ts, I tried doing:
(1/6 * 0.6) / (1/10 * .2) = 5, but this is incorrect.
What am I missing?