A box contains 7 pieces of candy: 1 green, 1 blue, and 5 red. You select one piece at random. Find the following probabilities.

Question

a.) P ( P(green or red ) =
b.) P ( P(green and red )
c.) P ( P(green or blue ) =
d.) P ( P(not(green or blue) ) =

Answer 1

first of all, since you are selecting one item, choice b) of green AND red is not possible, so pro(green and red) = 0

I will do a) , you do the rest
P(green or red):
there are 1 green and 5 red, so 6 of them are green OR red
P(green or red) = 6/7 , did you notice only 1 is not either green or red ??

do the others following the same logic