the net horizontal force on the block is reduced from 100 N to 75 N
the acceleration is reduced proportionally
75 / 100 = a / 0.8
Block A is accelerating with block B at a rate of 0.800 m/s^2 along a frictionl es surface. It suddenly encounters a surface that supplies 25.0 N a friction. What is the new acceleration?
(There is a picture with block A on top on a bigger block B with an arrow coming from block B that pints to 100 N pull)
_
|A|
|_B_| -> 100 N pull
0.8 m/s^2
1.0 m/s^2
0.6 m/s^2
0.4 m/s^2
1 answer