Asked by Luba
What is the greatest integer k such that 2k is a factor of 67!?
Answers
Answered by
Reiny
67! = 67*66*65*...*3*2
so (67*66*65*...*3)*(2) = 67!
k = 67*66*65*...*3
so (67*66*65*...*3)*(2) = 67!
k = 67*66*65*...*3
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