Find the zeros of the polynomial f(x)=2x3-7x2-3x+18

Answer 1

try factors of 18
f(1) = 2-7-3+18 ≠ 0
f(-1) ≠ 0
f(2) = 16 - 28 - 6 + 18 = 0 , so x-2 is a factor, and x = 2 is a zero

use either long algebraic division or synthetic division to divide f(x) by x-2 to get a quadratic. Solve this quadratic to find the other zeros.