Asked by Jada
In the outer space, a constant force is applied to a 32.5 kg probe initially at rest. The probe moves a distance of 100 m in 10 s. Could some one show me the step to step on how to find
(a) What acceleration does this force produce?
(b) What is the magnitude of the force?
(a) What acceleration does this force produce?
(b) What is the magnitude of the force?
Answers
Answered by
bobpursley
average velocity= 100/10 = 10 m/s
but average velocity= (vf+vo)/2=vf/2 so vf=20m/s
vf^2=vo^2+2ad
20^2=2*a*100
solve for a.
force= mass*a
but average velocity= (vf+vo)/2=vf/2 so vf=20m/s
vf^2=vo^2+2ad
20^2=2*a*100
solve for a.
force= mass*a
Answered by
Henry
a. V = d/t = 100m/10s = 10 m/s.
V = Vo + a*t = 10.
0 + a*10 = 10,
a = 1 m/s^2.
V = Vo + a*t = 10.
0 + a*10 = 10,
a = 1 m/s^2.
Answered by
Henry
F = M*a
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