can not
2*m*Cd(No3)2 + n* (NH2)2S -------> 2*k*CdS +2*j*NH4No3 maybe?
Cd 2m = 2k
so
k = m
2*m*Cd(No3)2 + n* (NH2)2S -------> 2*m*CdS +2*j*NH4No3
S 2n = 2m
so n = m
2*m*Cd(No3)2 + m* (NH2)2S -------> 2*m*CdS +2*j*NH4No3
N 4m +2m = 4 j
so j = 3m/2
2*m*Cd(No3)2 + m* (NH2)2S -------> 2*m*CdS + 3*m*NH4No3
2 Cd(No3)2 + (NH2)2S -------> 2 CdS + 3 NH4No3
check
O 12 = 9 nope
Balance this equation
2Cd(No3)2 + (NH2)2S-2CdS +2NH4No3
2 answers
This is what you wrote:
2Cd(No3)2 + (NH2)2S-2CdS +2NH4No3
Probably this is what you meant:
Cd(NO3)2 + (NH4)2S ==> CdS + NH4NO3
It is balanced this way.
Cd(NO3)2 + (NH4)2S ==> CdS + 2NH4NO3
2Cd(No3)2 + (NH2)2S-2CdS +2NH4No3
Probably this is what you meant:
Cd(NO3)2 + (NH4)2S ==> CdS + NH4NO3
It is balanced this way.
Cd(NO3)2 + (NH4)2S ==> CdS + 2NH4NO3