Question
When 0.100 L of 0.200 M K2C2O4 react with 0.150 L of 0.250 M BaBr2, BaC2O4 forms an insoluble precipitate. Calculate the final concentrations of the ions that remain in solution after the reaction.
I know how to get the net ionic equation (Ba2+ + C2O4- -> BaC2O4).
HOWEVER - I don't know why the three ions that remain in solution are K+, Br-, and Ba2+. Where did K+ come from? Thanks!
I know how to get the net ionic equation (Ba2+ + C2O4- -> BaC2O4).
HOWEVER - I don't know why the three ions that remain in solution are K+, Br-, and Ba2+. Where did K+ come from? Thanks!
Answers
bobpursley
K, Br are ions because the compounds formed go into solution as ions.
Ba ion is there because there is excess Ba ions. Look at the balanced equation.
Ba ion is there because there is excess Ba ions. Look at the balanced equation.