Asked by mi
How does the answer is pi/2 and not 0 for the question lim as t1-->-∞ from t1 to 0 integral (1/(1+x^2))dx
Answers
Answered by
Steve
remember that the principal values for arctan(x) lie in (-π/2,π/2)
so, the integral is
arctan(0) - arctan(t1)
and the limit as t1 -> -∞ arctan(t1) is -π/2
so, the integral is
arctan(0) - arctan(t1)
and the limit as t1 -> -∞ arctan(t1) is -π/2
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