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These two segments (DG and EH) should come out to be of equal distance. The coordinates of D are (-2h, 0) and G are (h,k). Usin...Asked by Anonymous
These two segments (DG and EH) should come out to be of equal distance.
The coordinates of D are (-2h, 0) and G are (h,k).
Using the distance formula I got the distance of DG to be the square root of 3h squared + k squared.
Using the distance formula I got the distance of EH to be -3h squared + k squared.
I know the two distances should be equal. I don't know why the second segment is coming out with that negative 3. I must have made a mistake somewhere... please help.
The coordinates of D are (-2h, 0) and G are (h,k).
Using the distance formula I got the distance of DG to be the square root of 3h squared + k squared.
Using the distance formula I got the distance of EH to be -3h squared + k squared.
I know the two distances should be equal. I don't know why the second segment is coming out with that negative 3. I must have made a mistake somewhere... please help.
Answers
Answered by
Reiny
You did not state the coordinates of E and H.
Answered by
kyle
how do i fid the surface are for this shape??? HELP!
Answered by
Anonymous
oops.
E (2h, 0)
A (0, 2k)
E (2h, 0)
A (0, 2k)
Answered by
Anonymous
oops again.
E (2h, 0)
H (-h, k)
E (2h, 0)
H (-h, k)
Answered by
Reiny
EH = √(2h-(-h))^2 + (0-k)^2)
= √(9h^2 + k^2)
which is the same as your other length
= √(9h^2 + k^2)
which is the same as your other length
Answered by
Anonymous
how could it be 9h squared? If you squared the 3? shouldn't that.. square be gone? I don't understand...
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