Calculate the number of potassium ions present in 7.45g of potassium oxide (atomic mass of K=39u)?
            
            
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                    Answered by
            bobpursley
            
    K2O potassium oxide
moles K2O=mass/formula mass= 7.45/(2*39+16)=.079moles
number K ions= 2*.079*avagradros number
    
moles K2O=mass/formula mass= 7.45/(2*39+16)=.079moles
number K ions= 2*.079*avagradros number
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