How many grams of H2 are needed to produce 11.61 grams of NH3?

Answer 1

2N + 3H2-----------> 2NH3

11.44g of NH3*(1 mole/17.03g)=0.6718 moles of NH3

The reaction is 2 moles of NH3: 3 moles of H2

0.6718 moles of NH3*(3 moles of H2/2 moles of NH3)=1.008 moles of H2

1.008 moles of H2*(2.02g/moles)=2.035g of H2

Part B

1.008 moles of H2*(6.022 x 10^23 molecules/mole)=6.068 x 10^23 molecules