Disp. = d1 [0o] + d2[75.8o].
Disp. = 2.92km[0o] + 1.71km[75.8o].
X = 2.92*Cos 0 + 1.71*Cos75.8 =
A car travels 2.92 km in the x-direction, then turns left 75.8◦ to the original direction and travels an additional distance of 1.71 km.
Calculate the x component of the car’s net displacement.
Let:
d1 =2.92km,
θ = 75.8◦ , and
d2 = 1.71 km .
answer in units of km
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