Asked by girl
a stone tied to the end of string 80 cm long whirled in a horizontal circle with a constant speed the stone makes 14 revolutions in 25 sec
a)what is the total angle in radian described by the stone in 25 sec
b)find the angular speed of the stone?
c)find the speed of the stone
d) find the direction and magnitude of the acceleration
a)what is the total angle in radian described by the stone in 25 sec
b)find the angular speed of the stone?
c)find the speed of the stone
d) find the direction and magnitude of the acceleration
Answers
Answered by
Damon
14 * 2 pi radians or 14 * 360 degrees
b) 28 pi radians/ 25 seconds = Omega
c) v = Omega * R = 28 pi * 0.8 / 25 meters/second
d) I assume you know formulas for centripetal acceleration so I do not have to derive v^2/r
either v^2/R or R omega^2 toward the middle
b) 28 pi radians/ 25 seconds = Omega
c) v = Omega * R = 28 pi * 0.8 / 25 meters/second
d) I assume you know formulas for centripetal acceleration so I do not have to derive v^2/r
either v^2/R or R omega^2 toward the middle
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