Question
The froghopper holds the world record for insect jumps. It can leap at an angle of 45.0° at a speed of 1.0 m/s. (a) Find the velocity (magnitude) at t = 1.0 seconds. (b) Find the position at t=1.0 seconds.
Answers
Steve
the vertical speed vy at time t is 1.0 sin45° - 9.8t
the horizontal speed vx is constant at 1.0 cos45°
the velocity v has magnitude |v| = √(vx^2 + vy^2)
the horizontal speed vx is constant at 1.0 cos45°
the velocity v has magnitude |v| = √(vx^2 + vy^2)