Asked by kj
A jogger maintains a speed of 2.5 m/s for 188 m until he encounters a stoplight, and he abruptly stops and waits 27 s for the light to change. He then resumes his exercise and maintains a speed of 3.6 m/s for the remaining 51 m to his home.
(a) What was his average velocity for this entire time interval?
m/s
(b) What were his maximum and minimum velocities, and how do they compare with this average?
vmax = m/s
vmin = m/s
(a) What was his average velocity for this entire time interval?
m/s
(b) What were his maximum and minimum velocities, and how do they compare with this average?
vmax = m/s
vmin = m/s
Answers
Answered by
bobpursley
figure the entire time (time=distance/rate).
then avg veloicty=total distance/totaltime
then avg veloicty=total distance/totaltime
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