Asked by Chartel
Doris invested some money at 7% and some money at 8%. She invested $6000 more at 8% than she did at 7%. Her total yearly interest from the two investments was $780. How much did Doris invest at each rate?
Answers
Answered by
Reiny
amount invested at 7% ---- x
amount invested at 8% = x+6000
solve for x:
.07x + .08(x+6000) = 780
amount invested at 8% = x+6000
solve for x:
.07x + .08(x+6000) = 780
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