Asked by Anna

The sum of three numbers is 21. One of the numbers is 2 more than twice
a second number and 2 less than the third number. Find the numbers.
Answered by Steve
x+y+z = 21
x = 2y+2
x = z-2
now just crank it out
Answered by Henry
1st. No. = X.
2nd No. = 2x + 2
3rd No. = (2x +2) + 2 = 2x + 4.

x + (2x+2) + (2x+4) = 21.
X = ?.
2x + 2 = ?
2x + 4 = ?.


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