assuming cg is at the 50cm mark.
Summing moments about the 50 cm mark.
clockwisetorque+counterclockwise torque=zero
String1*30cm-String2*20cm=0
String1/string2=2/3
but the sum of vertical tensions+weight=0
String1+string2=2kg*9.8N/kg
sting2*2/3 + sting2=19.6N
string2 tension= 19.6*3/5
string1tension=19.6*3/5*2/3=19.6*2/5 N
two thin strings support a 200g metre rule 20cm and 30cm from the ends.calculate the tension in each string.
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