nope on c. (-2)^2=4
g(a+1)=(a+1)^2+a+1 -1=a^2+2a+1+a=a^2+3a+1
Let f(x)=4x+4 and g(x)=x^2+x-1.Evaluate the following.
c. g(-2)=-2^2-2-1=-4-3=-7
f. g(a+1)=a^2+4a
Is c right? and f I got the wrong answer.
2 answers
g(x)=x^2+x-1
g(-2) = (-2)^2 + (-2) - 1
= 4 - 2 - 1
= 1
g(a+1) = (a+1)^2 + (a+1) - 1
= a^2 + 2a + 1 + a + 1 - 1
= a^2 + 3a
g(-2) = (-2)^2 + (-2) - 1
= 4 - 2 - 1
= 1
g(a+1) = (a+1)^2 + (a+1) - 1
= a^2 + 2a + 1 + a + 1 - 1
= a^2 + 3a