Asked by hi
find the domain and range of f^-1 where f(x)=1/3x+2
Answers
Answered by
Steve
If f(x) = 1/(3x+2)
then domain is x ≠ -2/3
range is y ≠ 0
f^-1(x) = (1-2x)/(3x)
and domain is x ≠ 0
range is y ≠ -2/3
If I parsed your function incorrectly, then fix it and see what you get.
then domain is x ≠ -2/3
range is y ≠ 0
f^-1(x) = (1-2x)/(3x)
and domain is x ≠ 0
range is y ≠ -2/3
If I parsed your function incorrectly, then fix it and see what you get.
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