length of hypotenus = 10
(6^2 + 8^2 = 10^2 )
So the radius of the large semicircle = 5
area of large semi-circle = 25π
so the total area of the two non-shaded regions is also 25π in^2
A semicircle is constructed along each side of a right triangle with legs 6 inches and 8 inches. The semicircle placed along the hypotenuse is shaded, as shown. What is the total area of the two non-shaded crescent-shaped regions? Express your answer in simplest form.
8 answers
area of large semi-circle = 25π/2
Argghh, of course, I think I need a nap.
That is wrong. That is not the answer.
The real answer is 24
A+B=C, the Pythagorean theorem states, in this case,
we want to minus C from the area of the two shaded areas that are outside but this will just end up in the right triangles area, so,
it will be 6*8/2=24
A+B=C, the Pythagorean theorem states, in this case,
we want to minus C from the area of the two shaded areas that are outside but this will just end up in the right triangles area, so,
it will be 6*8/2=24
Your AOPS account has been suspended for suspicious activity on ALCUMUS
haha very funny you dont even know what their account name is.
lmaooooo
1 answer