Asked by Kd
the triangle ABC., BC = 12cm, ABC = 80 degree and ACB = 30 degree
Calculate the area of triangle ABC.
asked by Kd
today at 3:06pm
angle BAC = 180-80-30 = ....
now find AB using the Sine Law.
Area of triangle = (1/2)(AB)(BC)sin80° = ....
you do the button-pushing.
Let me know what you get.
Is that correct
sin70/a = sin80/12
Calculate the area of triangle ABC.
asked by Kd
today at 3:06pm
angle BAC = 180-80-30 = ....
now find AB using the Sine Law.
Area of triangle = (1/2)(AB)(BC)sin80° = ....
you do the button-pushing.
Let me know what you get.
Is that correct
sin70/a = sin80/12
Answers
Answered by
Reiny
No, you are not matching them up correctly
should be :
sine(angle1)/side opposite that angle1 = sin(angle2)/side opposite angle2
so sin30/AB = sin70/12
continue ....
should be :
sine(angle1)/side opposite that angle1 = sin(angle2)/side opposite angle2
so sin30/AB = sin70/12
continue ....
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