Asked by Anonymous

The probability of three independent events occurring are 1/2,1/3,1/4. what is the probability that only one of them will occur
Answered by bobpursley
1/2*(2/3)*(3/4)+1/2*1/3*3/4 + 1/2 *2/3*1/4=? A little less than 1/2. compute it.
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