The plane containing the lines r1(t)=⟨1,−4,−1⟩+t⟨1,2,−2⟩ and r2(t)=⟨1,−4,−1⟩+t⟨1,0,3⟩ has scalar equation

Answer 1

the normal is r1×r2 = 6i-5j-2k
So, since the normal contains the point (1,-4,-1) the plane is
6x-5y-2z = 28