Asked by Carl
Find the exact value of integral t^2(2)^(-t^3). Upper limit is 1 and lower limit is 0.
Answers
Answered by
Steve
if you let u=-t^3 then
du = -3t^2 dt
So now you have ∫-1/3 2^u du
Now recall that ∫a^u du = 1/lna a^u + C
du = -3t^2 dt
So now you have ∫-1/3 2^u du
Now recall that ∫a^u du = 1/lna a^u + C
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