Question

Billy Bob “Bubba” Hickman is driving along one day messing with his cell phone instead of paying attention to what he is doing. He drives right off of a 25.0 foot high cliff at 42.4 mph.
How far from horizontally from the edge of the cliff does his truck land?
What is the direction and magnitude of Bubba’s truck’s velocity when it hits the ground?

Answer 1

His horizontal speed is 42.4 mph until he stops on the ground.
I have a hunch that you are using feet and stuff so will call gravity g = 32 ft/s^2
42/4 mph = 61.6 ft/s
Now how long to fall 25 ft?
25 =(1/2) g t^2 = 16 t^2
so t^2 = 25/16
t =5/4 seconds
now how far horizontal?
x = u t = 61.6 * 5/4
================
u = 61.6
v = g t = 32 *5/4 = 40 ft/s
so speed = sqrt (40^2 + 61.6^2)
tan angle below horizontal = (40/61.6)
so tan^-1(40/61.6)

Answer 2

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