height1 = -4.9t^2 - 17t + 96
height2 = -4.9t^2 + 22t
when are they equal?
solve for t, sub back into either of the equations.
An object is thrown downward with an initial speed of 17 m/s from a height of 96 m above the ground. At the same instant, a second object is propelled vertically up from ground level with a speed of 22 m/s. At what height above the ground will the two objects pass each other? The acceleration of gravity is 9.8 m/s2 . Answer in units of m.
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