will someone please double check my answer to this problem. the answer i get is a fraction, but not sure how to type it on here.

Question

4(4y+2)=2(1+6y)+8

16y+8=2+12y+8
16y+8=10+12y
-16 -16
8=-6+12y
+6 +6
14=12y
divide both by 12 and that leaves y=14/12 then reduce down to 7/6

is this correct?

Answer 1

12

Answer 2

i don't know how you are getting this answer. can you explain to me what i need to do please. thanks ive been out of school since 1995 and i never took algebra in high school so im having a tough time in college.

Answer 3

Your mistake here is when you go from

16y + 8 = 10 + 12y

to

8 = -6 + 12y.

You aren't subtracting the same thing from both sides; you're subtracting 16y from the left, but 16 from the right. Assuming you mean to subtract 16y, you should end up with

8 = 10 - 4y

Subtract 10 from each side:

-2 = -4y

Multiply each side by -1/4:
1/2 = y.

Answer 4

okay i worked through this problem but at the end, i need to multiply? I thought i divided both by 4?